If there are a 1s, b 3s, c 5s, d 7s and e 9s then:
a+3b+5c+7d+9e=35 and a+b+c+d+e=10.
a≤6, b,c≤8, d≤5, e=0 or 1.
Therefore, subtracting these equations:
2b+4c+6c+8e=25. But since the left side is even and the right side is odd, addition and subtraction alone cannot produce the required result.
The question doesn't eliminate multiplication or division.
Here's one solution:
(1+3+3)(9➗3×1+1×1+1×1)=7×5=35, using 6 1s, 3 3s and 1 9.