This is a function of the maximum solar altitude in degrees on day t of the year.

How can I find the average maximum height in total for June, July and August using integration, given that June 1st is the 152nd day of the year, and August 31st is the 243rd day of the year?

in Calculus Answers by

The formula doesn’t look right. Shouldn't it be division by 365, not multiplication? And to find the maximum h, we should use differentiation. Integration gives the area under a curve so the units would not make sense in this context. Differentiation would allow the maximum height in degrees to be calculated for the June-August period.

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

I think you mean h(t)=29.7+23.4cos(2π(x-172)/365). When x=172 the cosine argument=0 and cos(0)=1 so h(172)=29.7+23.4=53.1º.

The day number 172 lies between days 152-243, so the maximum altitude is 53.1º between June and August.

by Top Rated User (797k points)

Related questions

1 answer
asked May 7, 2013 in Geometry Answers by anonymous | 184 views
0 answers
asked Mar 12, 2013 in Geometry Answers by anonymous | 251 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
85,685 questions
91,353 answers
113,157 users