find the sum of geometric series described as : a1 =10 ,n=6 and r=4

how do i work it?
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2 Answers

The formula for the sum of a finite geometric series is : a((r^n)-1)/(r-1)

substituting values......10(4^6-1)/3=13,650

sum = thirteen thousand six hundred fifty.
by
Sn=a(r^n-1)/r-1

10(4^6-1)/4-1

=10(256-1)/3

=2550/3

=850
by

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