Find the value of for an infinite geometric series with S = 9 and r= 1/3

Find the value of      for an infinite geometric series with S = 9 and r= 1/3


 

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S=a/(1-r) for an infinite series because r^n=0 when n is infinite and r<1. So a=S(1-r)=9*2/3=6, where a is the first term.

by Top Rated User (1.2m points)

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