Use the standard normal distribution to find P(< -2.33 or Z >2.33)
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I read this as Z<-2.33 and Z>2.33. These areas are the same size. The table gives 0.9901 for Z<2.33, so for Z>2.33 we have 1-0.9901=0.0099. Therefore, the total of the two areas is 0.0198.

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