If log x /b-c=log y/c-a=log z/a-b, show that x^a*y^b*z^c=1

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?????????????? "log x/b-c" ??????????????... ??? maebee that be [log(x)/b] -c ????????????... or maebee log(x)/(b-c) ???????????... or maebee log(x/b) -c ?????????
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