find the value of y if (8,y) is to be equidistant from (1,-1) and (1,7)

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1 Answer

equidistant from 2 points meen it gotta be on perpendikular- bisekter av the line thru the 2 points..... points: (1,-1) & (1,7): this line is vertikal.... perp bisekter is horizontal.... averaej av y=-1 & y=7 is 3, so horizontal line is y=3... point yu want is(8,3)
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