find the point which is equidistant from (0,0), (3,1) and (6,0)

find the point which is equidistant from (0,0), (3,1) and (6,0)
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start: equidistans tween 2 points...(0,0) & (6,0)=perpendikular bisekter av line tween em

That be vertikal line thru (3,0)

point 3...(3,1) be on this line, so need tu go down that perpend bisekter rite distans

1 wae tu duit...get perpend bisekter tween  points (0,0) & (3,1)

Then find weer 2 perpendikular lines meet

Yuno it do thru midpoint av the line....(1.5, 0.5) & slope =90 deg tu linne tween em 2 points

me leev it tu yu tu du the dirty werk
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