Solve for x: tan-1[(√(1+x^2 )-√(1+x^2 ))/√(1+x^2+√(1-x^2 )) ]

Solve for x: tan-1[(√(1+x^2 )-√(1+x^2 ))/√(1+x^2+√(1-x^2 ))  ]
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The numerator is 0, because sqrt(1+x^2)-sqrt(1+x^2)=0 whatever the value of x. The denominator cannot be zero, so if x is tan^-1(...) then x=0. But x can also be 180 degrees or (pi) radians. Therefore, the comprehensive would be n(pi) or 180n.

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