if sin a= 24cos a,prove that 14tan a+25cos a-7sec a=30

Question

It can be done only by drawing figure of triangle and finding all trigonometric ratios

Answer 1

There's an error in the question: sin(a)=24cos(a)/7.

Then, tan(a)=24/7 so we can draw a right triangle with hypotenuse=√(24²+7²)=√625=25.

Therefore, sin(a)=24/25, cos(a)=7/25, sec(a)=25/7, and:

14tan(a)=14(24/7)=48; 25cos(a)=7; -7sec(a)=-25.

Adding these we get: 48+7-25=30 QED