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2 Answers

7+342ddd+ddffs56
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x² + y +8 [(x + 2y ² = a-z] + 2x ³ + (- 2z = 2. 4) + 10y - 5Z ³= k= 9 will give "SYNTAX ERROR". Try x² + y +8 [(x + 2y ²] = a-z + 2x ³ + (- 2z )= 2. 4 + 10y - 5z ³= k= 9 instead.
The practical application of this would be if the trajectory of something moving on the XY plane in a parabolic path represented by x² + y +8=9 is repeated for every point, in the trajectory of another object, moving in the same plane represented by x + 2y ²=9.
Also this will occur in co-incidence with the movement of a third object in the XZ plane following the trajectory 2x ³ - 3z + a=9, where a is an arbitrary real constant. So it will intersect the z axis at points (0,±∞). (The trajectory is like the letter S stretched to almost till its end).
Both of the above incidents need to occur simultaneously with a third incident represented by the movement of a fourth object in the YZ plane following the trajectory 2. 4 + 10y - 5z ³=9. It intersects the y axis at (0, 0.76). The trajectory is similar to that of the third object.
Lastly these movements is equated and represented by a constant k (as in k-mart)... which is equated to the real number 9

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