Combined income = X, combined expenses = Y. A's income is 5X/8 and B's income is 3X/8; A's expenses are 3Y/5 and B's expenses are 2Y/5. Assuming "save" means "income less expenses", A saves 5X/8-3Y/5; B saves 3X/8-2Y/5. They save 200Rs between them so X-Y=200 and Y=X-200. So A saves 5X/8-3(X-200)/5=(25X-24(X-200))/40=(X+4800)/40 and B saves 3X/8-2(X-200)/5=(15X-16(X-200))/40=(3200-X)/40.
A saves 120+X/40 and B saves 80-X/40, which must be positive so 80-X/40>0 and X<3200. Therefore A's income is less than 5*3200/8=2000Rs and B's income is less than 3*3200/8=1200Rs.
If we put S=combined savings we get A's savings=(X+24S)/40 and B's savings=(16S-X)/40, and X<16S, making A's income less than 10S and B's income less than 6S.
More info is required to determine their actual income. For example, if A saves 200Rs, then 120+X/40=200, X/40=80 and X=3200, making A's income 2000Rs and B's income 1200Rs. Knowing only the total savings is insufficient data.
We get a negative result for their incomes if they each save 200Rs, because X/4=Y/5 (5X/8-3X/8=3Y/5-2Y/5) and Y=5X/4 so that means that combined expenses exceeds income (X-Y=-X/4). If the ratios are swapped Y=4X/5, then we can determine X: 2X/5-3Y/8=2X/5-(3/8)(4/5)X=2X/5-3/10X=X/10=200, so X=2000Rs. Therefore A's income is 3/5 of this=1,200 and B's income is 800Rs (remember, we swapped the ratios).