FIND THE VALUE OF t if the standard diviation of 2t,3t,4t,5tand6t, is 2

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We need the mean: (2+3+4+5+6)t/5=4t.

Now we need the variance=[(-2t)2+(-t)2+0+(t)2+(2t)2]/5=2t2, so standard deviation=√(2t2)=t√2.

Therefore t√2=2 and t=√2.

by Top Rated User (1.2m points)

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