a cubic function P, has P(x) intercept equal to 5. Also P(1)=7 and P(2)=14. Find the particular equation for P(x)
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1 Answer

Let P(x)=a₀+a₁x+a₂x²+a₃x³ where a₀,...a₃ are constant coefficients.

P(0)=5 (intercept), so a₀=5. Let a₃=1.


P(1)=7=5+a₁+a₂+1, a₁+a₂=1, a₂=1-a₁


2a₁+4a₂=1=2a₁+4-4a, 2a₁=3, a₁=3/2, a₂=1-3/2=-½.


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