∫{(3x2-10)/(x2-4x+4)}dx=
∫{3+(12x-22)/(x2-4x+4)}dx.
(12x-22)/(x2-4x+4)=(12x-22)/(x-2)2=A/(x-2)+B/(x-2)2,
A(x-2)+B=Ax-2A+B=12x-22,
A=12, -2A+B=-22, -24+B=-22, so B=2.
(12x-22)/(x2-4x+4)=12/(x-2)+2/(x-2)2,
∫{3+(12x-22)/(x2-4x+4)}dx=3∫dx+12∫dx/(x-2)+2∫(x-2)-2dx=
3x+12ln|x-2|-2/(x-2)+C, where C is integration constant.