Suppose that g:[0,1] -> [0,1] is a continuous and strictly increasing function such that g(0)=0 and g(1)=1. Under these hypotheses g(x) has an inverse function g^-1 : [0,1] -> [0,1] such that

g^-1(g(x)) =x and g(g^-1(x)) =x for all x E [0,1]

Show that if xf is a fixed point of g(x) then xf is also a fixed point of g^-1(x)
in Calculus Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

Related questions

1 answer
asked Feb 18, 2021 in Other Math Topics by anonymous | 615 views
0 answers
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
731,520 users