findal all soultion of cos2x=sinx on inyerval of [0,2pi)

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1 Answer

cos(2x)=1-2sin2(x)=sin(x),

2sin2(x)+sin(x)-1=0,

(2sin(x)-1)(sin(x)+1)=0.

sin(x)=1/2, x=π/6, 5π/6 and sin(x)=-1, x=3π/2.

by Top Rated User (1.2m points)

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