find using differentiation

1.cosecx+3logx+3secx
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1 Answer

Given cosecx + 3logx + 3secx

let ... 3logx = v

x^3 = 10^v

3lnx = vln10

3/x = ln10 dv/dx

dv/dx = 3/xln10

therefore

d[cosecx + 3logx + 3secx]/dx = -cosecxcotx + 3/xln10 + 3secxtanx

 

by Level 3 User (4.0k points)

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