T is the tangent to the curve y= x^2 +6x -4 at (1,3) and N is the normal to the curve y= x^2 - 6x + 18 at (4,10). Find the coordinates of the point of intersection of T and N
in Other Math Topics by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

y=x^2+6x-4 . . .


at x=1, tangent=8=slope

thats nuff ....up tu yu tu du the sekond half

the "normal" is 90 deg tu the kerv, & slope av normal=-1/tangent

Related questions

1 answer
asked Dec 5, 2014 in Other Math Topics by peter kon piom | 103 views
1 answer
asked Jun 2, 2013 in Algebra 2 Answers by anonymous | 135 views
1 answer
1 answer
asked Apr 23, 2013 in Calculus Answers by saranya Level 1 User (200 points) | 109 views
0 answers
asked Mar 19, 2013 in Calculus Answers by anonymous | 155 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
82,892 questions
87,496 answers
3,942 users