in figure 6,PLRS is a straight line.

Given that RQ=2KL, find the value of tan x. 

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Assuming P is a right angle, PR2+PQ2=QR2, PR2+100=676, PR2=576, PR=24cm.

PL+LR=PR=24cm, 14+LR=24, LR=10cm. KL=RQ/2=26/2=13cm.

tanKR̂L=KL/LR=13/10=1.3, tan(x)=-1.3 because x=180-KR̂L and tan is negative in the second quadrant.

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