evaluate the integral [x^2(x^3+5)^6] dx

evaluate the integral  [x^2(x^3+5)^6] dx
in Calculus Answers by Level 1 User (320 points)

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1 Answer

Let u=x3+5, then du=3x2dx, so x2dx=du/3.

The integral becomes ⅓∫u6du=u7/21+C=(x3+5)7/21+C, where C is constant.

by Top Rated User (1.2m points)

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