log(3+x) - log(x-4) = log2

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1 Answer

 

log(3+x) - log(x-4) = log2

log (3+x) /(x -4)  = log 2         [ logm - log n = log m/n    ]

remove log sign both sides

(3+x ) / (x -4) = 2

3+ x = 2 * (x - 4)

3 + x = 2x - 8

3 + 8 = 2x -x

11 = x

x = 11

by Level 4 User (5.5k points)

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