log2+16log16/15+12log25/24+7log81/80

find the value of
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log10(2)=0.3010299956639827 . . . 16/15=1.066666666666666666... . . then log(1.06....)=0.02802872361381538 . . . then multipli that bi 16=0.44845957782104606 this soon get teedeeus...yu du the rest
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