find the product of (j + 7)(j – 7)

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4 Answers

(j+7)(j-7)

=j*j+j*-7+7*j+7*-7

=j^2-7j+7j-49

=j^2-49

this is the difference of 2 squares (j^2-7^2)
by
j^2-7j+7j-49
by
j^2-7j+7j-49

j^2-49
by

If j=√-1, then (j+7)(j-7)=j2-49=-50.

(In engineering j is often used to represent the imaginary √-1, which is also represented by i.)

by Top Rated User (1.2m points)

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