f(x)=(4x)(sqrtx)+(7/x^2sqrtx)

f(x)=[(4x)(sqrtx)+(7/x^2sqrtx)]

 

find f'(x)
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1 Answer

f(x) = 4x^(3/2) + 7x^(-5/2)

f ' (x) = (3/2)(4x^1/2) + (-5/2)(7x^(-7/2)

f ' (x) = 6x^(1/2) - (35/2)x^(-7/2)

.

Note:  If you meant f(x) = 4x^(3/2) + 7/(x^(2sqrtx)) then I'll leave it as an exercise for you to solve.
by Level 13 User (103k points)

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