help pleasssseeeeeee <3
in Algebra 2 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Descartes’  rule of signs:

f(x) has 2 changes of sign, implying at most two positive zeroes.

f(-x)=3x⁴+5x³-x²+8x+4 has 2 changes of sign, implying at most two negative zeroes.

The degree of f(x) is 4, so the number of complex zeroes could be 4-(2+2)=0.

In actual fact, there are 2 complex zeroes and two real positive zeroes.

Complex zeroes always come in conjugate pairs, so in this case there are none, 2 or 4. With two positive zeroes we have 2 negative zeroes or 2 complex zeroes.

by Top Rated User (781k points)

Related questions

1 answer
asked Oct 6, 2013 in Algebra 1 Answers by Confused | 155 views
2 answers
0 answers
asked Oct 29, 2012 in Algebra 2 Answers by anonymous | 188 views
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
85,299 questions
90,692 answers
2,171 comments
98,402 users