find by double integration the area of the cardioide  r=a(1+cos x)
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In polar coordinates the cardioid is r=a(1+cosθ).

The area of an infinitesimal sector of the cardioid is ½r2dθ=½a2(1+cosθ)2dθ.

The integral which gives us the area A is therefore the sum of these infinitesimals:

A=½a20(1+2cos(θ)+cos2(θ))dθ; cos2θ=½(cos(2θ)+1),

A=½a20(1+2cosθ+½(cos(2θ)+1))dθ=½a2[θ+2sinθ+¼sin(2θ)+θ/2]0=3πa2/2.

This only involves a single integral. Generally A=∫dA=∫∫f(x,y)dxdy=∫∫f(r,θ)rdrdθ. Therefore:

A=θ=0θ=2πr=0r=a(1+cos(θ))rdrdθ=0[r2/2]0a(1+cos(θ)dθ=0(½a2(1+cos(θ))2)dθ.

A=½a20(1+2cos(θ)+cos2(θ))dθ=3πa2/2, which is what we had before.

by Top Rated User (1.2m points)

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