Given y=1/32 (x+2)2 the 2 is an exponent you have to find the vertex axis of symmetry and direction of opening
asked Apr 29, 2013 in Algebra 2 Answers by anonymous

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The x+2 squared is positive so the opening is as in the arms of a U, directed upwards away from the vertex, which is at (-2,0) because the curve goes no lower than this point. The axis of symmetry is the x value of the vertex because the vertex sits on the axis of symmetry, the vertical line, x=-2.

answered Jan 10 by Rod Top Rated User (487,420 points)
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