find the vertex axis of symmetry direction of opening for y=1/32 (x+2)2

Question

Given y=1/32 (x+2)2 the 2 is an exponent you have to find the vertex axis of symmetry and direction of opening

Answer 1

The x+2 squared is positive so the opening is as in the arms of a U, directed upwards away from the vertex, which is at (-2,0) because the curve goes no lower than this point. The axis of symmetry is the x value of the vertex because the vertex sits on the axis of symmetry, the vertical line, x=-2.