-x-3z=-2  

3x+y-2z=5  

2x+2y+z=4
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1 Answer

-x-3z=-2 3x+y-2z=5 2x+2y+z=4

1) -x - 3z = -2
2) 3x + y - 2z = 5
3) 2x + 2y + z = 4

Multiply equation 2 by 2.

2 * (3x + y - 2z) = 5 * 2
4) 6x + 2y - 4z = 10

Subtract equation 3 from equation 4.

  6x + 2y - 4z = 10
-(2x + 2y +  z =  4)
-----------------------
  4x        - 5z  =  6
5) 4x - 5z = 6

Multiply equation 1 by 4.

4 * (-x - 3z) = -2 * 4
6) -4x - 12z = -8

Add equation 5 to equation 6.

 -4x - 12z = -8
+(4x -  5z =  6)
----------------
      - 17z = -2
-17z = -2
z = 2/17    <<<<<<<<<<<<<<<<<<<<<<

Plug that into equation 1 to solve for x.

-x - 3z = -2
-x - 3(2/17) = -2
-x - 6/17 = -2
-x = -2 + 6/17
-x = -1 11/17
x = 1 11/17    <<<<<<<<<<<<<<<<<<<<<<
It will be easier to use that as an improper fraction: 28/17

Plug the values for x and z into equation 2 and solve for y.

3x + y - 2z = 5
3(28/17) + y - 2(2/17) = 5
84/17 + y - 4/17 = 5
80/17 + y = 5
y = 5 - 80/17
y = 85/17 - 80/17
y = 5/17    <<<<<<<<<<<<<<<<<<<<<<

We'll use equation 3 to check the answer

2x + 2y + z = 4
2(28/17) + 2(5/17) + 2/17 = 4
56/17 + 10/17 + 2/17 = 4
68/17 = 4
4 = 4

We can use equation 2, also.

3x + y - 2z = 5
3(28/17) + 5/17 - 2(2/17) = 5
84/17 + 5/17 - 4/17 = 5
85/17 = 5
5 = 5

They check.

x = 28/17, y = 5/17, z = 2/17
by Level 11 User (78.4k points)

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