what is the sum of 11/8+11/72+11/648+11/5832

The sum of infinite geometric series
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1 Answer

This is equivalent to (11/8)(1+1/9+1/92+1/93)=

(11/8)(1-1/94)/(1-1/9)=(11/8)(6560/6561)(9/8)=

(99/64)(6560/6561)=1.546639 approx

Sum to infinity:

(11/8)(1/(8/9))=(11/8)(9/8)=99/64=1.54675.

by Top Rated User (1.2m points)

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