What is the question. These three points are not collinear (do not lie on the same straight line).
They could lie on a parabola y=ax2+bx+c:
(1) Plug in (1,-2): -2=a+b+c
(2) Plug in (-1,-4): -4=a-b+c
(3) Plug in (2,11): 11=4a+2b+c
We have three equations and three unknowns.
Subtract eqn (2) from eqn (1): 2=2b, so b=1.
Now plug b=1 into the other two eqns:
(2) becomes -4=a-1+c, so a+c=-3; (3) becomes 11=4a+2+c, so 4a+c=9.
Now we have two eqns:
a+c=-3
4a+c=9
Do this subtraction:
4a+c-(a+c)=9-(-3)=12,
3a=12, so a=4, therefore 4+c=-3, c=-7, and y=4x2+x-7.
All three points lie on this curve.