need help please...what is n2-n-12/n2-4n=(n-4)(n+3)/(n-2)(n+2)

Question

My granddaughter asked me to help with this. Homework problem ... I would like to help her understand concepts so she can apply to other problems. Her problem was: n2-n-12/over/n2-4n=(n-4)(n+3)/over/(n-2)(n+2)

Answer 1

(n²-n-12)/(n²-4n)=(n+3)(n-4)/(n(n-4))=(n+3)/n or 1+3/n where n≠4.