Using your model, predict the year in which the value of the car will be equal to $1,000
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1 Answer

log(1000)=log(4.067×1035)+log(x-15.899),

log(1000)-log(4.067×1035)=-15.899log(x),

log(x)=32.609274/15.899=2.051 approx.

x=112.47 approx.

by Top Rated User (1.2m points)

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