Please help I need the six trigonometric functions meaning the sine, cosine, tangent, cosecant, secant, and cotangent.
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Assuming that a and b are the legs of a right triangle such that tanθ=a/b; and c is the hypotenuse, such that a²+b²=c², then tanθ=6/9=⅔, c=√(36+81)=√97.

So we have:

sinθ=a/c=6/√97=6√97/97 in standard form;



cotθ=3/2 or 1½,



√97=9.8484 approx.

sinθ=0.6092, cosθ=0.9138, tanθ=0.6667,

cscθ=1.6415, secθ=1.0943, cotθ=1.5.

by Top Rated User (788k points)

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