its A maths on chapter 2, surds and indices
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3 divided by 1 minus the square rt. of 3 over 3
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(1-√3)/(2+√3) - (1/√3) = {√3(1-√3) - (2+√3)} / √3(2+√3) = (√3-3-2-√3) / (3+2√3)

 = -5 / (3+2√3) = -5(3-2√3) / (3+2√3)(3-2√3) = -(15-10√3) / -(12-9)

 = (15-10√3) / 3 = 5(3-2√3) / 3

The answer is: 5(3-2√3) / 3  

 

     

 

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