integral of x / sqrt ( 1-x^2)

x / sqrt ( 1 - x^2)

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1 Answer

Let u2=1-x2, then 2udu=-2xdx, xdx=-udu.

∫xdx/√(1-x2)=-∫udu/u=-∫du=-u=-√(1-x2).

So the solution is C-√(1-x2), where C is the integration constant.

by Top Rated User (1.2m points)

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