how would you calculate the following integral?

integral of: sec^2(sqrt x)/ sqrt x
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1 Answer

Let I=∫(sec2(√x)/√x)dx.

Let y2=x, then 2ydy=dx, so:

I=∫(sec2(y)/y)(2ydy)=2∫sec2(y)dy=2tan(y)+C=2tan(√x)+C, where C is integration constant.

by Top Rated User (1.2m points)

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