Write an equation of the line containing the given point and parallel to the given line. Express in y = mx + b form.
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(-3,6); 7x = 3y + 2
Write an equation of the line containing the given point
and parallel to the given line. Express in y = mx + b form.

As always, start by finding the slope of the given line.
7x = 3y + 2
3y = 7x - 2
y = 7/3 x - 2/3

To be parallel to the given line, the line we want will
have the same slope, 7/3.

We find the y-intercept of the new line by solving
y = mx + b for b: b = y - mx. Then, we plug in the
x and y values of the point we were given.

b = 6 - (7/3 * -3)
b = 6 - (-7)
b = 6 + 7
b = 13

The equation we want is y = 7/3 x + 13
by Level 11 User (78.4k points)

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