Find the line which goes through the point (2,-5) and is perpendicular to the line 3y-7x=2

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3y-7x=2 can be written y=(7x+2)/3 which has a slope of 7/3. the slope of the perpendicularto this is -3/7, so using intercept-slope notation for the point (2,-5), y+5=(-3/7)(x-2); y=-5-3x/7+6/7=-3x/7-29/7 or 7y+3x+29=0. The red line is 3y-7x=2 and the blue line is 7y+3x+29=0.

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