9x^2-16/2x+6
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1 Answer

(9x2-16)/(2x+6)=(3x-4)(3x+4)/[2(x+3)]=

(3x-4)(3x+9-5)/[2(x+3)]=

(3x-4)(3(x+3)-5)/[2(x+3)]=

(3x-4)(3/2-[(5/2)/(x+3)]).

by Top Rated User (1.2m points)

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