(7y^2-3y)=(8y^2-8y) A.-y^2+5y B.15y^2-11y C. -y^2+5y D. y^2-5y

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2 Answers

y^2(7-8)+y(-3+8)=0=-y^2+5y=0 (answer C) can be solved: y(-y+5)=0: y=0 or 5.
by Top Rated User (1.2m points)

Given (7y^2-3y)=(8y^2-8y)
7y^2-3y-8y^2+8y=0
5y-y^2=0
y(5-y)=0
y=0 or y=5

Algebra Topics

by Level 8 User (30.1k points)

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