how do you factor and solve w^3-w^2-4w+4=0

how do you factor and solve w^3-w^2-4w+4=0  ?
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1 Answer

w3-w2-4w+4=0=w2(w-1)-4(w-1)=(w2-4)(w-1)=(w-2)(w+2)(w-1).

So w=2, -2 or 1.

by Top Rated User (1.2m points)

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