2x^3+8x^2-32x-128=0

Find The roots and their multiplicity.
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1 Answer

We can write this as: 2x(x^2-16)+8(x^2-16)=0=(2x+8)(x^2-16)=2(x+4)(x-4)(x+4)=2(x-4)(x+4)^2, so the roots are x=4 (double root) and -4.

by Top Rated User (1.2m points)

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