will integration by parts be used to solved this problem?
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1 Answer

Let I=∫x2e-xdx.

Let u=x2, du=2xdx; dv=e-xdx, v=-e-x.

I=∫udv=uv-∫vdu=-x2e-x+2∫xe-xdx=-x2e-x+2J, where J=∫xe-xdx.

Let u=x, du=dx.

J=uv-∫vdu=-xe-x+∫e-xdx=-xe-x-e-x.

I=-x2e-x-2xe-x-2e-x=-e-x(x2+2x+2).

CHECK

dI/dx=e-x[(x2+2x+2)-(2x+2)]=x2e-x✔️

by Top Rated User (1.2m points)

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