2f(5f-2)-10(f-3f+6)=-8f(f+4)+4(2f^2-7f)

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1 Answer

f-3f+6=-2f+6; 2f(5f-2)-10(-2f+6)=-8f(f+4)+4(2f2-7f),

10f2-4f+20f-60=-8f2-32f+8f2-28f,

10f2+16f-60=-60f,

10f2+76f-60=0,

5f2+38f-30=0, f=(-38±√(382+600))/10=(-38±√2044)/10=0.721062 or -8.321062 approx.

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