y=10x/(8x^2 +1)
in Algebra 1 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

The horizontal asymptote is determined by considering large values of x. 10x/(8x²+1) becomes 10x/8x²=5/(4x). This approaches zero as the magnitude of x gets very large, positive or negative, so the horizontal asymptote is y=0, the x-axis.

by Top Rated User (652k points)

Related questions

1 answer
asked Feb 28, 2014 in Calculus Answers by Isabella Level 1 User (260 points) | 167 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
83,040 questions
87,759 answers
1,974 comments
4,590 users