y=2x-1;(2,-2)

write an equation of a line parallel to the given line but passing through the given point
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1 Answer

Parallel line has same gradient so y=2x+a where a is a constant to be found by plugging in the given point:

-2=4+a, a=-6 and y=2x-6.

Another way: y+2=2(x-2), y+2=2x-4, y=2x-6.

by Top Rated User (1.2m points)

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