just need help evaluating the given limit.
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Let δ be a very small positive quantity.

When x=1-δ, x1/(1-x)=(1-δ)/δ=1/δ-1. As δ→0, 1/δ→∞ (limit approached from the left).

When x=1+δ, x1/(1-x)=(1+δ)/(-δ)=-1/δ+-1. As δ→0, 1/δ→-∞ (limit approached from the right).

The two limits are dissimilar, so limit as x→1 is indeterminate.

As x→1- (x approaches 1 from the left, the negative side) the limit is infinity.

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