if an object starts from rest, what constant acceleration will allow it to travel 500 m in 10 s?

Question

Integration/antidifferentiation must be used to answer this problem.

Answer 1

p = position

po = starting position

v = velocity

vo = starting velocity

a = acceleration

t = time

p = po + vot + (1/2)at^2

500 = 0 + 0 + (1/2)a(10^2)

500 = (1/2)a(100)

5 = (1/2)a

a = 10 meters per second^2