factor completely. Pratice of factoring. Sum of odd powers.

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If we put a7+b7=0, then we know a=-b is a solution, that is, a+b is a factor. If we divide by this factor we will end up with another factor. The easiest way to divide is to use synthetic division with -b as the divisor:

-b | 1  0   0   0   0   0   0   b7

       1 -b b2 -b3 b4 -b5 b6 -b7

      1 -b b2 -b3 b4 -b5 b6 | 0

which translates to the polynomial a6-a5b+a4b2-a3b3+a2b4-ab5+b6.

a7+b7=(a+b)(a6-a5b+a4b2-a3b3+a2b4-ab5+b6).

by Top Rated User (1.2m points)

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